In most of our cases,
we are concerned with non-magnetic and conducting materials. We assume that the
material properties, such as conductivity, σ,
are spatially uniform and incompressible. In this chapter, we are going to
discuss about the electric force and the Lorentz force.
Generally, a particle
moving with velocity u and carrying
electric charge q, is subjected to
electromagnetic forces and governed by the following equation:
$\mathbf{f}=q{{\mathbf{E}}_{s}}+q{{\mathbf{E}}_{i}}+q\mathbf{u}\times
\mathbf{B}$ (21.1)
Here, Es is the electrostatic field and the first term
is the electrostatic force or Coulomb force which arises from the
mutual attraction or repulsion of electric charges. The second term is the
force which arises in the presence of time-varying magnetic field, since Ei is the electric field
induced by the varying magnetic field. Due to the motion of the charge in a
magnetic field, Lorentz force arises,
and this is given by the third term $q\mathbf{u}\times \mathbf{B}$.
Coulomb’s law says that
electrostatic field Es is
irrotational, and Gauss’s law fixes the divergence of Es. These laws are respectively given by:
$\nabla \cdot
{{\mathbf{E}}_{s}}={}^{{{\rho }_{e}}}/{}_{{{\varepsilon }_{0}}}$
(21.2)
$\nabla \times
{{\mathbf{E}}_{s}}=0$
(21.3)
ρe
is the total charge density (free plus bound charges) and ε0 is permittivity of free space. Introducing
electrostatic potential V, defined by
${{\mathbf{E}}_{s}}=-\nabla V$, equation (21.2) becomes:
${{\nabla
}^{2}}V=-{}^{{{\rho }_{e}}}/{}_{{{\varepsilon }_{0}}}$
(21.4)
On the other hand,
induced electric field Ei
has zero divergence, and finite rotational component. This is governed by
Faraday’s law:
$\nabla \cdot
{{\mathbf{E}}_{i}}=0$ (21.5)
$\nabla \times
{{\mathbf{E}}_{i}}=-\frac{\partial \mathbf{B}}{\partial t}$
(21.6)
Conveniently, we define
the total electric field as: E = Es
+ Ei and so we have:
Gauss’s law:
$\nabla \cdot \mathbf{E}={}^{{{\rho }_{e}}}/{}_{{{\varepsilon }_{0}}}$
(21.7)
Faraday’s law:
$\nabla \times \mathbf{E}=-\frac{\partial \mathbf{B}}{\partial t}$ (21.8)
Electrostatic
and Lorentz force: $\mathbf{f}=q(\mathbf{E}+\mathbf{u}\times \mathbf{B})$ (21.9)
Equations (21.7) and
(21.8), i.e. Gauss’s and Faraday’s law, determine uniquely the electric field
since the divergence and curl of the field are known and the boundary
conditions are specified. Equation (21.9) defines the electric field E and magnetic field B, where E is the force per unit charge on a test charge at rest in the observer’s frame. If the
charge is moving, the additional force $q\mathbf{u}\times \mathbf{B}$ appears
which is used to define B. However,
Newtonian relativity which is all that is required for MHD tells us that the
electric force relative to a moving frame fr
is equal to the electric force due to electric field at rest f, i.e. fr = f.



